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`int(secx."cosec"x)/(2cotx-secx"cosec x")dx` di equal toA. `(1)/(2)ln|sec2x+tan2x|+C`B. `ln|secx+"cosec x"|+C`C. `ln |secx+Tanx|+C`D. `(1)/(2)ln|secx+" cosec x"|+C` |
Answer» Correct Answer - A `I=int(sec x "cosec x")/(2cot x -sec x" cosec "x)dx` `=int(dx)/(2cos^(2)x-1)` `=intsec2xdx` `=(1)/(2)ln|sec 2x+tan2x_+C` |
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