1.

`int(sin^(6)x + cos^(6)x)/(sin^(2)xcos^(2)x)dx`

Answer» Correct Answer - `secx-"cosec"x+C`
`int(sin^(3)x+cos^(3)x)/(sin^(2)xcos^(2)x)dx=int(sin^(3)x)/(sin^(2)xcos^(2)x)dx+int(cos^(3)x)/(sin^(2)xcos^(2)x)dx`
`=int(sinx)/(cos^(2)x)dx+int(cosx)/(sin^(2)x)dx`
`=int tanxsecxdx+int cotx"cosec"xdx`
`=secx-"cosec"x+C`


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