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`int(sin^(6)x + cos^(6)x)/(sin^(2)xcos^(2)x)dx` |
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Answer» Correct Answer - `secx-"cosec"x+C` `int(sin^(3)x+cos^(3)x)/(sin^(2)xcos^(2)x)dx=int(sin^(3)x)/(sin^(2)xcos^(2)x)dx+int(cos^(3)x)/(sin^(2)xcos^(2)x)dx` `=int(sinx)/(cos^(2)x)dx+int(cosx)/(sin^(2)x)dx` `=int tanxsecxdx+int cotx"cosec"xdx` `=secx-"cosec"x+C` |
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