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`int sin (a+b)cos(ax+b) dx` |
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Answer» `int sin (ax+b)cos (ax+b)dx` माना `sin(ax+b)=t` `rArr a cos (ax+b)dx=dt` `rArr cos (ax+b)dx=(dt)/(a)` `=intt(dt)/(a)=(1)/(a).(t^(2))/(2)+c` `=(1)/(2a)sin^(2)(ax+b)+c` |
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