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`int((sin theta+cos theta))/(sqrt(sin 2theta))d theta` is equal toA. `log |cos theta-sin theta+sqrt(sin 2 theta)|+C`B. `log|sin theta - cos theta+sqrt(sin 2 theta)|+C`C. `sin^(-1)(sin theta+cos theta)+C`D. `sin^(-1)(sin theta +cos theta)+C` |
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Answer» Correct Answer - C Let `l=int(sin theta+cos theta)/(sqrt(1+sin 2 theta-1))d theta` `=int (sin theta+cos theta)/(sqrt(1-(sin theta-cos theta)^(2)))d theta` `"Put "sin theta - cos theta=t` `rArr" "l=int(1)/(sqrt(1-t^(2)))dt = sin^(-1)t+C` `=sin^(-1)(sin theta - cos theta)+C` |
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