InterviewSolution
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`int(sin(x-a))/(sin(x+a))dx` का मान ज्ञात कीजिए । |
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Answer» माना `" "I=int(sin(x-a))/(sin(x+a))dx` और `" "x+a=t` `rArr" "dx=dt` `therefore" "=int(sin(t-2a))/(sint)dt` `" "=int(sint.cos2a-costsin2a)/(sint)dt` `" "=intcos2adt-intsin2a.cott dt` `" "=tcos2a-sin2a.log|sint|+c` `" "=(x+a)cos2a-sin2a log|sin(x+a)|+c` `" "=xcos2a-sin2alog|sin(x+a)|c_(1)` `" "`(जहाँ `c_(1)=c+acos2a` है ) |
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