1.

int (sin " x")/(cos 3x.cos 2x) dx =

Answer»

`(1)/(3) " LOG cos 3X" + (1)/(2) "log cos " 2X + c `
`(1)/(3) " log | sec 3 X|" (1)/(2) ` log | sec 2x | + c
`(1)/(3) ` log | tan 3x | - `(1)/(2)` log | tan 2x | + c
none

Answer :B


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