1.

`int(sin2x)/(acos^(2)x+bsin^(2)x)dx` का मान ज्ञात कीजिए ।

Answer» माना `I=int((sin2x)/(acos^(2)x+bsin^(2)x))dx`
और `" "acos^(2)x+bsin^(2)x=t`
`rArr" "a.2cosx(-sinx)+b.2sinx.cosx=(dt)/(dx)`
`rArr" "sin2x(b-1)dx=dt`
`rArr" "sin2x.dx=(dt)/(b-a)`
`therefore" "I=int(dt)/((b-a).t)=(1)/(b-a).log|t|c`
`" "=(1)/(b-a)log|acos^(2)x+bsin^(2)x|+c`


Discussion

No Comment Found