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`int(sin2x)/(acos^(2)x+bsin^(2)x)dx` का मान ज्ञात कीजिए । |
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Answer» माना `I=int((sin2x)/(acos^(2)x+bsin^(2)x))dx` और `" "acos^(2)x+bsin^(2)x=t` `rArr" "a.2cosx(-sinx)+b.2sinx.cosx=(dt)/(dx)` `rArr" "sin2x(b-1)dx=dt` `rArr" "sin2x.dx=(dt)/(b-a)` `therefore" "I=int(dt)/((b-a).t)=(1)/(b-a).log|t|c` `" "=(1)/(b-a)log|acos^(2)x+bsin^(2)x|+c` |
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