1.

`int(sin2x)/(sin^4x+cos^4x)d x`A. `cot^(-1)(tan^(2)x)+c `B. `tan^(-1)(tan^(2)x)+c `C. `cot^(-1)(cot^(2)x)+c `D. `tan^(-1)(cot^(2)x)+c `

Answer» Correct Answer - B
` I= int(sin2x)/(sin^(4)x+cos^(4)x)dx`
`=int(2sinx cosx)/(sin^(4)x+cos^(4)x)dx`
`=int(2tanx sec^(2)x)/(1+tan^(4)x)dx `
`"Let " tan^(2)x=t " or " 2tanxsec^(2)xdx=dt`
` :. I=int(dt)/(1+t^(2))=tan^(-1)t+C=tan^(-1)(tan^(2)x)+C`


Discussion

No Comment Found

Related InterviewSolutions