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`int(sin2x)/(sin5x.sin3x)dx` का मान ज्ञात कीजिए । |
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Answer» माना `I=int(sin2x)/(sin5x.sin3x)dx=int(sin(5x-3x))/(sin5x.sin3x)dx` `=int(sin5x.cos3x-cos5x.sin3x)/(sin5x.sin3x)dx` `=int(sin5x.cos3x)/(sin5x.sin3x)dx-int(cos5x.sin3x)/(sin5x.sin3x)dx` `=intcot3x.dx-intcot5x.dx` `=(1)/(3)log|sin3x|-(1)/(5)log|sin5x|+c` |
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