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`int sin3x cos 4x dx` |
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Answer» `intsin3x cos 4x dx=(1)/(2) int 2 cos 4x sin 3x dx` `=(1)/(2)int(sin 7x-sinx)dx` `=(1)/(2)(-(cos7x)/(7)+cosx)+c` `=-(1)/(14)cos 7x+(1)/(2)cosx+c` |
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