1.

int(sinax-sinbx)/(cosax-cosbx)dx

Answer»

SOLUTION :`int(sinax-sinbx)/(cosax-cosbx)dx`
=`(2SIN((a-b)/2) X.cos((a+b)/2) x)/(-2sin((a+b)/2) x.sin((a-b)/2) x)dx`
=`-intcot((a+b)/2)xdx`
=`-2/(a+b) In abs(sin((a+b)/2)x)+C` =`1/k Inabs(sinkx)+C`


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