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`int(sinx-cosx)^(4)(sinx+cosx)dx` is equal toA. `(sin x - cosx)/(5)+C`B. `((sin x - cosx)^(5))/(5)+C`C. `((sin x-cosx)^(4))/(4)+C`D. `((sinx+cosx)^(5))/(5)+C` |
Answer» Correct Answer - B Let `l=int(sinx-cosx)^(4)(sinx +cosx)dx` Put`" "Sinx-cosx=t` `rArr" "(cos x+sin x)dx=dt` `therefore" "l=int t^(4)dt=(t^(5))/(5)+C=((sinx-cosx)^(5))/(5)+C` |
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