1.

`int(sinx)/(sin(x-alpha)) dx = ?`A. `x cos alpha + (sin alpha) log |sin (x-alpha)| + C`B. `x sin alpha + (sin alpha) log |sin (x-alpha) | + C`C. `x cos alpha - (sin alpha) log |sin(x-alpha) | + C`D. `x sin alpha - (sin alpha) log |sin (x-alpha)| + C`

Answer» Correct Answer - A
`I = (sin(x-alpha +alpha))/(sin(x-a)) dx = int(sin(x-alpha) cos alpha +cos(x-alpha)sinalpha)/(sin(x-alpha)) dx`
`= (cosalpha) int dx +(sinalpha) int cot (x- alpha) dx`.
`= xcosalpha+(sinalpha) log|sin(x-alpha) | +C`.


Discussion

No Comment Found