InterviewSolution
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`int(sinx)/(sin(x-alpha)) dx = ?`A. `x cos alpha + (sin alpha) log |sin (x-alpha)| + C`B. `x sin alpha + (sin alpha) log |sin (x-alpha) | + C`C. `x cos alpha - (sin alpha) log |sin(x-alpha) | + C`D. `x sin alpha - (sin alpha) log |sin (x-alpha)| + C` |
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Answer» Correct Answer - A `I = (sin(x-alpha +alpha))/(sin(x-a)) dx = int(sin(x-alpha) cos alpha +cos(x-alpha)sinalpha)/(sin(x-alpha)) dx` `= (cosalpha) int dx +(sinalpha) int cot (x- alpha) dx`. `= xcosalpha+(sinalpha) log|sin(x-alpha) | +C`. |
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