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`int(sqrt(x^2+10 x+24))/(x+5)dx` is equal toA. `sqrt(x^(2)+10x+24)+sec^(-1)(x+5)+c`B. `sqrt(x^(2)+10x+24)-"cosec"^(-1)(x+5)+c`C. `sec^(-1)(x+5)-sqrt(x^(2)+10x+24)+c`D. `sqrt(x^(2)+10x+24)-sec^(-1)(x+5)+c` |
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Answer» Correct Answer - D ` I=int(sqrt(x^(2)+10x+24))/(x+5)dx=int(sqrt((x+5)^(2)-1))/(x+5)dx` `"Put " x+5=sec theta implies dx=sec theta tan theta d theta ` `:. I=int(tan theta)/(sec theta)*sec theta tan theta d theta ` `=int(sec^(2) theta-1)d theta` `=tan theta-theta+C` `=sqrt(x^(2)+10x+24)-sec^(-1)(x+5)+c` |
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