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| 1. |
`int(tanax-cotbx)/(1+tanaxcotbx)dx=`A. `(-1)/(a+b)log{sin[(a+b)x]}+c`B. `(-1)/(a-b)log{cos[(a-b)x]}+c`C. `(-1)/(a+b)log{[cos(a+b)x]}+c`D. `(1)/(a-b)log[secax-secbx]+c` |
| Answer» Correct Answer - A | |