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`int(x^(3)+3x+4)/(sqrtx)dx`

Answer» `int(x^(3)+3x+4)/(sqrtx)`
`=int((x^(3))/(sqrtx)+(3x)/(sqrtx)+(4)/(sqrtx))dx`
`=intx^(5//2)dx+3intx^(1//2)dx+4 intx^(-1//2)dx`
`=(x^(7//2))/(7//2)+3.(x^(3//2))/(3//2)+4.(x^(1//2))/(1//2)+c`
`=(2)/(7)x^(7//2)+2x^(3//2)+8x^(1//2)+c`


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