`int (((x^(4) + 1))/((x^(2) + 1))) dx = ?`A. `(x^(3))/(3) + x - tan^(-1) x + C`B. `(x^(3))/(3) - x + 2 tan^(-1) x + C`C. `(x^(3))/(3)0 + x - 2 tan^(-1) x +C`D. none of these

`int (((x^(4) + 1))/((x^(2) + 1))) dx = ?`A. `(x^(3))/(3) + x - tan^(-

1.	`int (((x^(4) + 1))/((x^(2) + 1))) dx = ?`A. `(x^(3))/(3) + x - tan^(-1) x + C`B. `(x^(3))/(3) - x + 2 tan^(-1) x + C`C. `(x^(3))/(3)0 + x - 2 tan^(-1) x +C`D. none of these
Answer» Correct Answer - B On dividing `(x^(4) + 1)` by `(x^(2) +1)`, we get `((x^(4)+1))/((x^(2) + 1)) = (x^(2) - 1) + 2/((1+x^(2)))`.

(i) `int(6x^(5) - 2/(x^(4)) - 7x + 3/x - 5 + 4e^(x) + 7^(x))dx` (ii) `int (8-x+2x^(3) -6/(x^(3)) +2x^(-5) + 5x^(-1)) dx` , (iii) `int (x/a+a/x+x^(a) +a^(x) + ax) dx`
Evaluate `int(secx)/((secx+tanx)) dx`.
Evaluate `int ((cosx - 2cos 2alpha)/(cosx - cos alpha)) dx`.
Evaluate : (i) `int((4-5 cosx)/(sin^(2)x))dx` , (ii) `int((1-cos2x)/(1+cos2x)) dx` (iii) `int (1)/(sin^(2)x cos^(2)x) dx` , (iv) `int(cos2x)/(cos^(2)x sin^(2) x) dx`
(i) `int(1)/((1+cos2x))dx` , (ii) `int (1)/((1-cos2x)) dx`
`int sqrt(1+sin2x)dx`
`int tan^(-1) ((sin2x)/(1+cos 2x))dx`
`intsqrt[1+sin2x]dx`A. `sinx + cosx + C`B. `-sinx + cos x + C`C. `sin x - cos x + C`D. `-sin x - cos x + C`
Evaluate : `intsqrt(1-sin2x)dx`.
Evaluate : (i) `int3x^(2)dx` , (ii) `int2^((x+3)) dx`