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`int(x - sinx)/(1-cosx)dx` का मान ज्ञात कीजिए । |
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Answer» `int(x-sinx)/(1-cosx)dx=int(x-2sin.(x)/(2)cos.(x)/(2))/(2sin^(2).(x)/(2))dx` `=int(x)/(2sin^(2).(x)/(2))dx-int(2sin.(x)/(2)cos.(x)/(2))/(2sin^(2).(x)/(2))dx` `=(1)/(2)int x" cosec"^(2)(x)/(2)dx- intcot.(x)/(2)dx` `=(1)/(2)[x int" cosec"^(2)(x)/(2)dx-int{(d)/(dx)x int" cosec"^(2)(x)/(2)dx}dx]-intcot.(x)/(2)dx` `=(1)/(2)[x.((-cot.(x)/(2)))/((1)/(2))-int1.((-cot.(x)/(2)))/((1)/(2))dx]-intcot.(x)/(2)+c` `=-x cot.(x)/(2)+intcot.(x)/(2)dx- int cot.(x)/(2)dx+c` `=-x cot.(x)/(2)+c` |
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