1.

`int x sinx sec^(3)x dx` is equal toA. `(1)/(2)[ sec^(2)x-tanx]+c`B. `(1)/(2)[x sec^(2)x-tanx]+c`C. `(1)/(2)[x sec^(2)x+tanx]+c`D. `(1)/(2)[ sec^(2)x+tanx]+c`

Answer» Correct Answer - B
`intx sinx sec^(3)x dx=intx sinx(1)/(cos^(3)x)dx`
`=int x tanx sec^(2)x dx `
`=x int secx(secx tanx)dx-int[int secx(secx tanx)dx]dx+C`
`=x(sec^(2)x)/(2)-int(sec^(2)x)/(2)dx+C`
`=x(sec^(2)x)/(2)-(tanx)/(2)+C`


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