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`int x sinx sec^(3)x dx` is equal toA. `(1)/(2)[ sec^(2)x-tanx]+c`B. `(1)/(2)[x sec^(2)x-tanx]+c`C. `(1)/(2)[x sec^(2)x+tanx]+c`D. `(1)/(2)[ sec^(2)x+tanx]+c` |
Answer» Correct Answer - B `intx sinx sec^(3)x dx=intx sinx(1)/(cos^(3)x)dx` `=int x tanx sec^(2)x dx ` `=x int secx(secx tanx)dx-int[int secx(secx tanx)dx]dx+C` `=x(sec^(2)x)/(2)-int(sec^(2)x)/(2)dx+C` `=x(sec^(2)x)/(2)-(tanx)/(2)+C` |
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