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`int(x+x^(2/3)+x^(1/6))/(x(1+x^(1/3)))dx` equalsA. `(3x^((2)/(3)))/(4)+6tan^(-1)(x^((1)/(6)))+C`B. `(3x^((2)/(3)))/(2)+6tan^(-1)(x^((1)/(6)))+C`C. `(3x^((2)/(3)))/(10)+6tan^(-1)(x^((1)/(6)))+C`D. `(3x^((2)/(3)))/(5)+6tan^(-1)(x^((1)/(6)))+C` |
Answer» Correct Answer - B Put `x=u^(6)` `therefore" "I=6int(u^(5)+u^(3)+1)/(1+u^(2))du` `=6intu^(3)du+6int(du)/(1+u^(2))` `=(3u^(4))/(2)+6 tan^(-1)u+C` `=(3x^((2)/(3)))/(2)+6 tan^(-1)(x^((1)/(6)))+C` |
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