1.

int2x^3cosx^2dx

Answer»

SOLUTION :`int2x^3cosx^2dx` [PUT `x^2=t
Then 2xdx=dt]
=`intx^2.cosx^2 .2xdx`
=`intt.cost.dt` [1=1st
cost=2nd]
=`t.sint-int1sintdt`
=tsint+cost+C
=`x^2sinx^2+cosx^2+C`


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