1.

int2xcos3xcos2xdx

Answer»

Solution :`INT2XCOS3XCOS2XDX`
=`INTX[cos5x+cosx]dx`
=`intx.cos5xdx+intx.cosxdx`
=`X.(sin5x)/5-int1.(sin5x)/5dx+x.sinx-int1.sinxdx`
1/5.xsin5x+1/25cos5x+xsinx+cosx+C


Discussion

No Comment Found

Related InterviewSolutions