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int2xsin2xcosxdx |
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Answer» SOLUTION :`int2xsin2xcosxdx` =`INTX(sin3x+sinx)dx` =`intx.sin3xdx+intxsinxdx` =`x.(-(COS3X)/3)-int1.(-(cos3x)/3)dx+x.(-COSX)-int1.(-cosx)dx` =-1/3xcos3x+1/9sin3x-xcosx+sinx+C |
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