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int2xsin2xcosxdx

Answer»

SOLUTION :`int2xsin2xcosxdx`
=`INTX(sin3x+sinx)dx`
=`intx.sin3xdx+intxsinxdx`
=`x.(-(COS3X)/3)-int1.(-(cos3x)/3)dx+x.(-COSX)-int1.(-cosx)dx`
=-1/3xcos3x+1/9sin3x-xcosx+sinx+C


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