InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
`int32x^(3)(logx)^(2)` dx is equal otA. `8x^(4)(logx)^(2)+C`B. `x^(4){8(logx)^(2)-4log x+1}+C`C. `x^(4){8(logx)^(2)-4logx}+C`D. `x^(3){(logx)^(2)+2logx}+C` |
|
Answer» Correct Answer - B `int 32x^(3)(logx)^(2)dx` On using integration by parts, we get `32{(logx)^(2).(x^(4))/(4)-int 2 log x.(1)/(x).(x^(4))/(4)dx}` `=8x^(4)(logx)^(2)-16intx^(3)log x dx` Again using integration by parts, we get `8x^(4)(logx)^(2)-16{logx.(x^(4))/(4)-int(1)/(x).(x^(4))/(4)dx}` `=8x^(4)(logx)^(2)-4x^(4)logx+4int x^(3)dx` `=8x^(4)(logx)^(2)-4x^(4)logx+x^(4)+C` `=x^(4)[8(logx)^(2)-4logx+1]+C` |
|