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intcos^-1xdx |
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Answer» SOLUTION :`intsox^-1x.dx` [Choose cos^-1x=1st and 1=2nd FUNCTION] =`cos^-1x.x-int(-1)/sqrt(1-xx^2) .XDX` =`xcos^-1x+int1/sqrt(1-xx^2) .xdx` [PUT `1-x^2=t^2` Then xdx=-tdt] =`xcos^-1x+int(-tdt)/t` `xcos^-1x-t+C` =`xcos^-1x-sqrt(1-x^2) +C` |
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