1.

intcos^-1xdx

Answer»

SOLUTION :`intsox^-1x.dx` [Choose cos^-1x=1st
and 1=2nd FUNCTION]
=`cos^-1x.x-int(-1)/sqrt(1-xx^2) .XDX`
=`xcos^-1x+int1/sqrt(1-xx^2) .xdx`
[PUT `1-x^2=t^2`
Then xdx=-tdt]
=`xcos^-1x+int(-tdt)/t`
`xcos^-1x-t+C`
=`xcos^-1x-sqrt(1-x^2) +C`


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