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`intcos^(3)xe^(log(sinx))dx` is equal toA. `(-sinn^(4)x)/(4)+C`B. `-(cos^(4)x)/(4)+C`C. `(e^(sinx))/(4)+C`D. None of these |
Answer» Correct Answer - B Let `l=int cos^(3)x e^(log sinx)dx=int cos^(3)x sin x dx` Put `cos x = t rArr - sin x dx = dt` `therefore" "l=-int t^(3)dt=-(t^(4))/(4)+C=-(cos^(4)x)/(4)+C` |
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