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`intcos^(4)2xdx` |
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Answer» `intcos^(4)2xdx=int(cos^(2)2x)^(2)dx` `=int((1+cos4x)/(2))^(2)dx` `=(1)/(4)int(1+2 cos 4x+cos^(2)4x)dx` `=(1)/(4)int(1+2 cos 4x+(1 + cos8x)/(2))dx` `=(1)/(8) int(3+4 cos 4x+cos 8x)dx` `=(1)/(8)(3x+(4 sin 4x)/(4)+(sin 8x)/(8))+c` `=(3x)/(8)+(1)/(8)sin 4x+(1)/(64)sin 8x+c` |
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