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intcos^4xdx

Answer»

SOLUTION :`intcos^4xdx=INT((1+cos2x)/2)^2dx`
=`1/4 int(1+2cos2x+cos^2 2X)DX`
=`1/4 int(1+2cos2x+(1+cos4x)/2)dx`
=`1/4 int(3/2+2cos2x+1/2cos4x)dx`
=3x/8+1/4sin2x+1/32sin4x+C


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