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intcos^4xdx |
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Answer» SOLUTION :`intcos^4xdx=INT((1+cos2x)/2)^2dx` =`1/4 int(1+2cos2x+cos^2 2X)DX` =`1/4 int(1+2cos2x+(1+cos4x)/2)dx` =`1/4 int(3/2+2cos2x+1/2cos4x)dx` =3x/8+1/4sin2x+1/32sin4x+C |
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