1.

intcos^5xsin^3xdx

Answer»

SOLUTION :`intcos^5xsin^3xdx`
=`intcos^5x(1-cos^2x)sinxdx`
[PUT cosx=t Then sinxdx=-DT]
=`intt^5(1-t^2).(-dt)=INT(t^7-t^5)dt`
=`1/8t^8-1/6cos^6x+C`


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