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intcos^5xsin^3xdx |
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Answer» SOLUTION :`intcos^5xsin^3xdx` =`intcos^5x(1-cos^2x)sinxdx` [PUT cosx=t Then sinxdx=-DT] =`intt^5(1-t^2).(-dt)=INT(t^7-t^5)dt` =`1/8t^8-1/6cos^6x+C` |
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