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intdx/(1+tanx) |
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Answer» SOLUTION :`I=intdx/(1+tanx)` =`INT(cosxdx)/(sinx+cosx)` =`1/2int((cosx-sinx)+(cosx+sinx))/(sinx+cosx)DX` =`1/2int(cosx-sinx)/(sinx+cosx)dx+1/2intdx` =`1/2Inabs(cosx-sinx)+1/2x+c` `because d/dx(sinx+cosx)=cosx-sinx` |
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