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intdx/(e^x-1) |
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Answer» SOLUTION :`I=intdx/(e^x-1)` =`inte^-x/(1-e^-x)DX` LET `1-e^-x=t` `e^-xdx=dt` `THEREFORE I=intdt/t` =`Inabst+C` =`Inabs(1-e^-x)+c` =`Inabs((e^x-1)/e^x)+c` |
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