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`inte^(tanx)(sinx-secx)dx` is equal toA. `e^(tanx)cosx +C`B. `e^(tanx)sinx +C`C. `-e^(tanx)cosx +C`D. `e^(tanx)sec x +C` |
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Answer» Correct Answer - C `I=inte^(tanx)(sinx-secx)dx` `=int sinx e^(tanx)dx-int secx e^(tanx)dx` `=-e^(tanx)cosx+int cos x e^(tanx)sec^(2)x dx-int sec x e^(tanx) dx` `= -cosx e^(tanx) +C` |
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