1.

inte^x((2+sin2x)/(1+cos2x))dx

Answer»

SOLUTION :`I= inte^x((2+sin2x)/(1+cos2x))DX`
=`inte^x((2+2sinxcosx)/(2cos^2x))dx`
=`inte^x(sec^2x+tanx)dx`
=`inte^xsec^2xdx+inte^xtanxdx`
=`inte^xsec^2xdx+e^xtanx-inte^xsec^2xdx+c`
=`e^xtanx+c`


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