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inte^x/x(1+xInx)dx |
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Answer» Solution :`inte^x/x(1+xInx)DX` =`inte^xdx+inte^xInxdx` [INTEGRATING by parts TAKING `e^x` as FIRST and 1/x as second function.] =`e^x.Inx-inte^x.Inxdx+inte^xInxdx+C` =`e^x.Inx+C` |
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