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    				| 1. | 
                                    Integrate the following functions 1/(1-tanx) | 
                            
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Answer» Solution :1/(1-tanx) = COSX/(cosx-sinx)  `1/2[((cosx-sinx)-(-sinx-cosx))/(cosx-sinx)]` =`1/2[1-(-sinx-cosx)/(cosx-sinx)]` therefore` INT dx/(1-tanx)` =`1/2 [x-log|cosx-sinx|]+C`  | 
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