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Integrate the following functions 1/sqrt(x^2+2x+2) |
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Answer» SOLUTION :`x^2+2x+2 = (x+1)^2+1` THEREFORE` int1/sqrt(x^2+2x+2) dx` =`INT 1/sqrt((x+1)^2+1) dx` =`LOG|(x+1) + sqrt((x+1)^2+1)|+c` =`log |x+1+sqrt(x^2+2x+2)|+c` |
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