1.

Integrate the following functions 1/(x+xlogx)

Answer»

Solution :Put 1+logx = t. Then DT = 1/X dx
THEREFORE `INT 1/(x+xlogx) dx = int 1/(1+logx)x) dx`
`int 1/t dt = log|t| +c`
=`log|1+logx| +c`


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