1.

Integrate the following functions (2cosx- 3sinx)/(6cosx +4sinx)

Answer»

Solution :`(2cosx-3sinx)/(6cosx +4 SINX)`
`(2cosx- 3sinx)/(2(2sinx +3cosx))`
Let t = 2sinx +3cosx.
Then dt = (2cosx-3sinx)dx
therefore` INT (2cosx-3sinx)/(6cosx+4 sinx) dx`
=`int 1/2 (dt)/t`
=`1/2 log|2sinx+3 cosx|+c`


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