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Integrate the following functions (2cosx- 3sinx)/(6cosx +4sinx) |
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Answer» Solution :`(2cosx-3sinx)/(6cosx +4 SINX)` `(2cosx- 3sinx)/(2(2sinx +3cosx))` Let t = 2sinx +3cosx. Then dt = (2cosx-3sinx)dx therefore` INT (2cosx-3sinx)/(6cosx+4 sinx) dx` =`int 1/2 (dt)/t` =`1/2 log|2sinx+3 cosx|+c` |
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