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Integrate the following functions (2x)/(1+x^2) |
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Answer» SOLUTION :Put `1+x^2 = t Then DT = 2xdx` therefore `int (2X)/(1+x^2) dx = int (dt)/t` =`log|t|+c = log|1+x^2| +c` =`log(1+x^2) +c` (because `1+x^2>0`) |
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