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Integrate the following functions (2x)/(1+x^2)

Answer»

SOLUTION :Put `1+x^2 = t Then DT = 2xdx`
therefore `int (2X)/(1+x^2) dx = int (dt)/t`
=`log|t|+c = log|1+x^2| +c`
=`log(1+x^2) +c` (because `1+x^2>0`)


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