InterviewSolution
Saved Bookmarks
| 1. |
Integrate the following functions (3x)/(1+2x^4) |
|
Answer» Solution :Let t = `sqrt2 x^2`. Then DT = `2 sqrt2 x dx` `gt x dx = 1/(2 sqrt2) dt` therefore` INT (3x)/(1+2x^4) dx = int 3/(1+t^2) 1/(2sqrt2) dt` =`3/(2 sqrt2) tan^-1 t+C` `3/(2 sqrt2) tan^-1 (sqrt2 x^2)+c` |
|