1.

Integrate the following functions (3x^2)/(x^6+1)

Answer»

Solution :LET t = `x^3`. Then `dt = `3x^2 DX`
THEREFORE` int (3x^2)/(x^6+1) dx`
=`int dt/(t^2+1) = tan^-1 t+C`
=`tan^-1(x^3)+c`


Discussion

No Comment Found

Related InterviewSolutions