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Integrate the following functions (3x^2)/(x^6+1) |
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Answer» Solution :LET t = `x^3`. Then `dt = `3x^2 DX` THEREFORE` int (3x^2)/(x^6+1) dx` =`int dt/(t^2+1) = tan^-1 t+C` =`tan^-1(x^3)+c` |
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