1.

Integrate the following functions: cos(2x)/(cosx+sinx)^2

Answer»

SOLUTION :`(COS2X)/(cosx+sinx)^2 = (cos^2x-sin^2x)/(cosx+sinx)^2`
`=(cosx-sinx)/(cosx+sinx)`
PUT cosx+sinx = t
Then dt = (-sinx+cosx) DX
therefore` INT(cos2x)/(cosx+sinx)^2 dx`
=`int dt/t = log|t|+c`
=`log|cos+sinx|+c`


Discussion

No Comment Found

Related InterviewSolutions