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Integrate the following functions: cos(2x)/(cosx+sinx)^2 |
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Answer» SOLUTION :`(COS2X)/(cosx+sinx)^2 = (cos^2x-sin^2x)/(cosx+sinx)^2` `=(cosx-sinx)/(cosx+sinx)` PUT cosx+sinx = t Then dt = (-sinx+cosx) DX therefore` INT(cos2x)/(cosx+sinx)^2 dx` =`int dt/t = log|t|+c` =`log|cos+sinx|+c` |
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