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Integrate the following functions: (cos2x-cos 2alpha)/(cosx-cos alpha) |
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Answer» Solution :`(cos2x-cos2alpha)/(cosx-cos alpha)` `(2cos^2x-1-(2 cos^2 alpha-1))/(cosx-cos alpha)` =`(2cos^x-2 cos^2 alpha)/(cosx-cos alpha)` `(2(cosx-cos alpha)(cosx+cos alpha))/(cosx-cos alpha)` =`2(cosx+cosalpha)` therefore` int(cos2x-cos2 alpha)/9cosx -cos alpha) DX` =`INT2(cosx+cos alpha) dx` =`2[sinx+xcos alpha]+C` |
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