1.

Integrate the following functions: (cos2x-cos 2alpha)/(cosx-cos alpha)

Answer»

Solution :`(cos2x-cos2alpha)/(cosx-cos alpha)`
`(2cos^2x-1-(2 cos^2 alpha-1))/(cosx-cos alpha)`
=`(2cos^x-2 cos^2 alpha)/(cosx-cos alpha)`
`(2(cosx-cos alpha)(cosx+cos alpha))/(cosx-cos alpha)`
=`2(cosx+cosalpha)`
therefore` int(cos2x-cos2 alpha)/9cosx -cos alpha) DX`
=`INT2(cosx+cos alpha) dx`
=`2[sinx+xcos alpha]+C`


Discussion

No Comment Found

Related InterviewSolutions