1.

Integrate the following functions (e^(2x) - 1)/(e^(2x) +1

Answer»

Solution :`(e^(2X)-1)/(e^(2x)+1) = (e^x(e^x-e^-x))/(e^x(e^x-e^+x)) = (e^x-e^-x)/(e^x+e^-x)`
Let `t = e^x+e^-x`. Then
dt = `(e^x-e^-x) dx`
therefore `INT (e^(2x) -1)/(e^(2x)+1) dx = int(e^x-e^-x)/e^x+e^-x)dx`
`int (dt)/t = LOG |t|+c`
= `log|e^x+e^-x|+c`


Discussion

No Comment Found

Related InterviewSolutions