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Integrate the following functions e^(tan^-1 x)/(1+x^2) |
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Answer» SOLUTION :Let t = `tan^-1x`. Then dt = `1/(1+x^2) dx` THEREFORE` int e^(tan^-1x)/(1+x^2) dx = int e^x dt` =`e^t+C = e^(tan^-1x) +c` |
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