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Integrate the following functions sin^-1 ((2x)/(1+x^2)) |
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Answer» SOLUTION :`int sin^-1((2x)/(1+X^2)) dx` =`int 2 tan^-1x dx = 2int 1 XX tan^-1 x dx` =`2[tan^-1x xx x-int 1/(1+x^2) dx]` `2[x tan^-1 x -1/2 int(2x)/(1+x^2) dx]` =`2 [x tan^-1x -1/2 log (1+x^2)]+c` =`2 x tan^-1x -log(11+x^2)+c` |
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