1.

Integrate the following functions: sin 3x cos4x

Answer»

SOLUTION :`sin 3X cos 4x = cos 4x sin 3x
=1/2[sin(4x+3x)-sin(4x-3x)]
=1/2[sin7x-sinx]
therefore `int SIN3X cos4x dx`
=1/2[-cos(7X)/7+cosx]+C


Discussion

No Comment Found

Related InterviewSolutions