InterviewSolution
Saved Bookmarks
| 1. |
Integrate the following functions sin(ax+b) cos(ax+b). |
|
Answer» Solution :SIN(ax+b) cos(ax+b) =1/2 sin(2(ax+b)) = 1/2 sin(2ax+2b) THEREFORE `int sin (ax+b) cos (ax+b) dx` =`1/2 xx - (cos(2ax+2b))/(2a) +c` = `-1/(4a) cos(2ax+2b)+c` `sin THETA cos theta = 1/2 SIN2THETA` |
|