1.

Integrate the following functions sin(ax+b) cos(ax+b).

Answer»

Solution :SIN(ax+b) cos(ax+b)
=1/2 sin(2(ax+b)) = 1/2 sin(2ax+2b)
THEREFORE `int sin (ax+b) cos (ax+b) dx`
=`1/2 xx - (cos(2ax+2b))/(2a) +c`
= `-1/(4a) cos(2ax+2b)+c`
`sin THETA cos theta = 1/2 SIN2THETA`


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