1.

Integrate the following functions sinx/(1+cosx)^2

Answer»

Solution :LET t = 1+cosx.
Then DT = -SINX dx
`gt sinx dx = -dt`
THEREFORE `int sinx/(1+cosx)^2 dx = int 1/t^2 xx -dt = 1/t+c = 1/(1+cosx) +c`


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