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Integrate the following functions sinx/(1+cosx)^2 |
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Answer» Solution :LET t = 1+cosx. Then DT = -SINX dx `gt sinx dx = -dt` THEREFORE `int sinx/(1+cosx)^2 dx = int 1/t^2 xx -dt = 1/t+c = 1/(1+cosx) +c` |
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