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Integrate the following functions tan^-1x |
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Answer» Solution :`int tan^-1x DX ` =`int 1 XX tan^-1x dx` =`tan^-1x xx x-int1/(1+x^2) C dx` =`xtan^-1x -1/2 int (2x)/(1+x^2) dx` =`x tan^-1 x-1/2 LOG (1+x^2)+c` |
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